November 21, 2008
Would Someone Please Explain Relativity to Me?
I need to know how it affects the probability that the tiny moth inside my car will eventually leave the Cruiser if I open the windows.
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And what that experience might be like from the moth's point of view. If there are any paratroopers who read blogs, they might be able to tell me. (And when, BTW, did we stop using paratroopers for our regular armed forces; do they still have them in Special Forces? They must. Please advise.)
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Posted by: Attila Girl at
08:57 AM
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1
paratroopers == airborne, such as the 82nd and 101st. Most (all?) special operators have their airborne badge.
http://en.wikipedia.org/wiki/Master_Parachutist_Badge
Posted by: I R A Darth Aggie at November 21, 2008 10:24 AM (1hM1d)
2
I need to know how it affects the probability that the tiny moth inside my car will eventually leave the Cruiser if I open the windows.
It affects the probability proportionally to
1-√(v²/c²
where v is the relative velocity between the moth and the car. If the moth is moving at 5 cm/sec, this is around 0.9999999998 --- in other words, about 2 parts in 10 billion.
And what that experience might be like from the moth's point of view.
A whole lot like when the car is stopped.
The wind moving into the windows, though, probably cause it a lot of trouble.
And when, BTW, did we stop using paratroopers for our regular armed forces...?
What you mean "we"?
where v is the relative velocity between the moth and the car. If the moth is moving at 5 cm/sec, this is around 0.9999999998 --- in other words, about 2 parts in 10 billion.
And what that experience might be like from the moth's point of view.
A whole lot like when the car is stopped.
The wind moving into the windows, though, probably cause it a lot of trouble.
And when, BTW, did we stop using paratroopers for our regular armed forces...?
What you mean "we"?
Posted by: Charlie (Colorado) at November 21, 2008 02:03 PM (bE/kw)
3
I need to know how it affects the probability that the tiny moth inside my car will eventually leave the Cruiser if I open the windows.
It affects the probability proportionally to
1-√(v²/c²
where v is the relative velocity between the moth and the car. If the moth is moving at 5 cm/sec, this is around 0.9999999998 --- in other words, about 2 parts in 10 billion.
And what that experience might be like from the moth's point of view.
A whole lot like when the car is stopped.
The wind moving into the windows, though, probably cause it a lot of trouble.
And when, BTW, did we stop using paratroopers for our regular armed forces...?
What you mean "we"?
where v is the relative velocity between the moth and the car. If the moth is moving at 5 cm/sec, this is around 0.9999999998 --- in other words, about 2 parts in 10 billion.
And what that experience might be like from the moth's point of view.
A whole lot like when the car is stopped.
The wind moving into the windows, though, probably cause it a lot of trouble.
And when, BTW, did we stop using paratroopers for our regular armed forces...?
What you mean "we"?
Posted by: Charlie (Colorado) at November 21, 2008 02:06 PM (bE/kw)
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